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82 lines (77 loc) · 1.76 KB
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/*
Author: Sudip Ghosh (sudipghosh9333@gmail.com)
q23.cpp (c) 2022
Desc: merging two sorted arrays
Created: 2022-08-29T10:51:55.465Z
Modified: 2022-08-29T10:55:00.226Z
*/
#include <iostream>
using namespace std;
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class ListNode
{
public:
int val;
ListNode *next;
ListNode() : val(0), next(nullptr) {}
ListNode(int x) : val(x), next(nullptr) {}
ListNode(int x, ListNode *next) : val(x), next(next) {}
};
class Solution
{
public:
ListNode *mergeTwoLists(ListNode *list1, ListNode *list2)
{
ListNode *head = new ListNode(0);
ListNode *curr = head;
while (list1 && list2)
{
if (list1->val < list2->val)
{
curr->next = list1;
list1 = list1->next;
}
else
{
curr->next = list2;
list2 = list2->next;
}
curr = curr->next;
}
if (list1)
{
curr->next = list1;
}
if (list2)
{
curr->next = list2;
}
return head->next;
}
};
int main()
{
Solution s;
ListNode *list1 = new ListNode(1);
list1->next = new ListNode(2);
list1->next->next = new ListNode(4);
ListNode *list2 = new ListNode(1);
list2->next = new ListNode(3);
list2->next->next = new ListNode(4);
ListNode *list = s.mergeTwoLists(list1, list2);
while (list)
{
cout << list->val << " ";
list = list->next;
}
cout << endl;
}